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What will be printed when this program is executed?
int f(int x)
{
if(x <= 4)
return x;
return f(--x);
}
void main()
{
printf("%d ", f(7));
}
{
if(x <= 4)
return x;
return f(--x);
}
void main()
{
printf("%d ", f(7));
}
- a)4 5 6 7
- b)1 2 3 4
- c)4
- d)Syntax error
Correct answer is option 'C'. Can you explain this answer?
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Most Upvoted Answer
What will be printed when this program is executed?int f(int x){ if(x ...
In this recursive function call the function will return to main caller when the value of x is 4. Hence the output.
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Community Answer
What will be printed when this program is executed?int f(int x){ if(x ...
Understanding the Function
The function `f(int x)` is designed to return a specific value based on the input `x`.
- If `x` is less than or equal to 4, it directly returns `x`.
- If `x` is greater than 4, it decrements `x` by 1 and calls itself recursively with the new value.
Analyzing the Execution
Let's analyze what happens when `f(7)` is called:
1. First Call: `f(7)`
- Since 7 > 4, it calls `f(6)` after decrementing x.
2. Second Call: `f(6)`
- Since 6 > 4, it calls `f(5)` after decrementing x.
3. Third Call: `f(5)`
- Since 5 > 4, it calls `f(4)` after decrementing x.
4. Fourth Call: `f(4)`
- Since 4 <= 4,="" it="" returns="">
Returning the Value
Now let's trace back:
- `f(4)` returns 4.
- `f(5)` receives 4 from `f(4)`, but it doesn't change the return value, so it effectively returns 4.
- `f(6)` also receives 4 from `f(5)` and returns 4.
- Finally, `f(7)` receives 4 from `f(6)` and returns 4.
Final Output
Thus, when `main()` executes `printf("%d ", f(7));`, it prints `4`.
So, the correct answer is option C: 4.
The function `f(int x)` is designed to return a specific value based on the input `x`.
- If `x` is less than or equal to 4, it directly returns `x`.
- If `x` is greater than 4, it decrements `x` by 1 and calls itself recursively with the new value.
Analyzing the Execution
Let's analyze what happens when `f(7)` is called:
1. First Call: `f(7)`
- Since 7 > 4, it calls `f(6)` after decrementing x.
2. Second Call: `f(6)`
- Since 6 > 4, it calls `f(5)` after decrementing x.
3. Third Call: `f(5)`
- Since 5 > 4, it calls `f(4)` after decrementing x.
4. Fourth Call: `f(4)`
- Since 4 <= 4,="" it="" returns="">
Returning the Value
Now let's trace back:
- `f(4)` returns 4.
- `f(5)` receives 4 from `f(4)`, but it doesn't change the return value, so it effectively returns 4.
- `f(6)` also receives 4 from `f(5)` and returns 4.
- Finally, `f(7)` receives 4 from `f(6)` and returns 4.
Final Output
Thus, when `main()` executes `printf("%d ", f(7));`, it prints `4`.
So, the correct answer is option C: 4.
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What will be printed when this program is executed?int f(int x){ if(x <= 4) return x; return f(--x);}void main(){ printf("%d ", f(7));}a)4 5 6 7b)1 2 3 4c)4d)Syntax errorCorrect answer is option 'C'. Can you explain this answer?
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